10 si 11, dau coroana
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Răspuns:
10) m(∡ACB)= 180°- ( 70°+60°)=50°⇒m(∡ACI)= m(∡ACB)/2=25°
m(∡AIB)= 180°-(m∡ABI+m∡BAI)= 180°- ( 35°+30°)= 115°
11) m(∡CBD)+m(∡DCB)=180°-106°=74°⇒m(∡ABC)+m(∡ACB)=74°·2=148°⇒
m(∡A)= 180°-148°=32°
Explicație pas cu pas: