a) AD-inaltime
In triunghiul ADC, m(D)=90°=>Teorema lui Pitagora:
[tex] {ad}^{2} = {ac}^{2} - {dc}^{2} [/tex]
DC-jumatate din BC=>DC=7 cm
[tex] {ad}^{2} = 144 - 49 \\ ad = \sqrt{95} \\ ad = 19 \sqrt{5} \: cm[/tex]
b) Aria=
[tex] \frac{b \times h}{2} [/tex]
[tex] \frac{14 \times 19 \sqrt{5} }{2} = \frac{226 \sqrt{5} }{2} = 113 \sqrt{5} \: cm[/tex]
