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Madeline123
a fost răspuns

Prin tratarea a x g amestec echimolecular de acid acetic si acid propionic cu zinc, se degaja 112 litri H2, masurati in conditii normale. Masa de amestec echimolecular este:

Răspuns :

nHâ‚‚=112/22.4=5 moli

2R-COOH+Zn→(RCOO)₂Zn+H₂

2 Moli R-COOH...........1 mol Hâ‚‚

x Moli R-COOH...........5 mol Hâ‚‚

x=5*2=10moli amestec echimolecular de acid acetic si acid propionic

nacid acetic = nacid propionic=10/2= 5 moli

M acid acetic =60 g/mol

M acid propionic=74 g/mol

m amestec=5*60+5*74=300+370=670 g

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