- se foloseste relatia : n=m : M, in care n= nr. moli ; m=masa subst. (g )
M= masa molara (g/moli )
320 g Br2
MBr2=2 . 80 =160------>160g/moli
n=320 g : 160 g/moli =2moli brom
190 g MgCl2
M=24+ 2.35,5=95----->95g/moli
n=190g :95g/moli =2moli MgCl2
50 g CaCO3
M=40+12+3.16=100------>100g/moli
n=50 g : 100g/moli=0,5 moli CaCO3
La primul nu ai scris ce hidroxid este , rezolva-l singur dupa modele
