Răspuns:
1) a) 2x+2y+ax+ay= 2(x+y)+a(x+y)=(x+y)(2+a)
b) x+ax-y-ay=x(1+a) - y(1+a)= (1+a)(x-y)
2) a) x³-16x=x(x²-16)=x(x-4)(x+4)
b)y³-9y= y(y²-9)= y(y-3)(y+3)
3) a) x³+x²++x+1= (x³+x²) + (x+1)= x²(x+1)+(x+1)=(x+1)(x²+1)
b) x³+3x²-x-3= (x³+3x²) - (x+3)= x²(x+3)-(x+3)=(x+3)(x²-1)=(x+3)(x-1)(x+1)
Explicație pas cu pas:
