Răspuns:
x-2≠0 x≠2 ; x+2≠0 ; x≠-2 ; x(x²-4)/(x-2)² =x((x-2)(x+2)/(x-2)²=x(x+2)/(x-2); x(x²+4x+4)/(x+2)(x_2)=x(x+2)²/(x+2(x-2)=x(x+2)/(x-2)
