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Nechitamagdale
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Daca x=3√5,calculeaza :
b) (x²+x+1)²-(x²+1)(x²-1)-9(x+3)(x-3)=

c) (x²+x)-(x²-x+2)²-(2x-1)²=


De preferat sa-l inlocuim pe x la urma
Va roooog. Urgentttt

Răspuns :

Mikigabi22gabi
b)  xla 4+x²+1+2x³+2x²+2x-x la4 +1-9x²+81=
-6x²+2x³+2x+83=
-6*(3√5)²+2*(3√5)³+2*(3√5)+83=
-270+270√5+6√5+83=
-187+276√5
276√5-187
c)x²+x-x la 4 -x²-4+2x³-4x²+2x-4x²-1+4x=
-xla4+2x³-8x²+7x-5=
(-3√5)la4+2*(3√5)³-8*(3√5)²+7*(3√5)-5=
-2025+270√5-360+21√5-5=
291√5-2 390

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