Răspuns :
K I M=AK + A I=39 +127=166--->1mol=166g
CsBr M=ACs + ABr=133 +80=213--->1mol=213g
AgNO3 M=AAg + AN +3AO=108 + 14 +3.16=170-->
----> 1mol=170g
FeCO3 M=AFe +AC +3AO=56+ 12+3.16=116--->
--->1mol=116g
Cs2SO4 M=2ACs +AS +4AO=2.133 +32 +4.16=362
---> 1mol=362g
Mg3(PO4)2 M=3.24 +2.31 +8.16=262--->1mol=262g
mai verifica calculele !