-calculez masa de substanta pura
p=m,px100/ m,i----> mp= 1000x80/100g= 800g MgCO3 pur
M,MgCO3= 84g/mol
M,MgO= 40g/mol
M,CO2=44g/mol
M,MgCl2=95g/mol
M,CaCO3=100g/mol
84g.......................40g.........44g
MgCO3-------> MgO + CO2
800g.....................x..............y x= 381g y=419g
40g............................95g
MgO + 2HCl----> MgCl2 + H2O
381g....................................x x=905gMgCl2
44g.....................................100g
CO2 + Ca(OH)2-----> CaCO3 + H2O
419g..................................x x= 952g CaCO3
