M,CaO=56g/mol
M,H2O=18g/mol
M,Ca(OH)2=74g/mol
CaO consuma o masa de apa in reactia, din care rezulta Ca(OH)2
56g........18g..........74g
CaO +H2O----> Ca(OH)2
560g........x...............y
y= 740g Ca(OH)2 este substanta aflata in solutie,md
x= 180g H2O
ms= md+ m,apa= 740+(1500-180)=>2060g
C= mdx100/ms= 740x100/2060=.....................calculeaza !!!1