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Inocentiubebe
a fost răspuns

324+3 x{386+[48+2 x(5 xA -16 x 5 )]}=1866
Este o problema de clasa a-IV-a
va rog!

Răspuns :

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[tex]324+3*\{386+[48+2*(5a -16*5 )]\}=1866|-324 \\ 3*\{386+[48+2*(5a-80)]\}=1542|:3 \\ 386+(48+10a-160)=514|-386 \\ 48+10a-160=128|+160 \\ 10a+48=288|-48 \\ 10a=240 \\ \boxed{a=24}[/tex]
Deva
324+3x{386+[48+2x(5A-80)]}=1866
3x{386+[48+2x(5A-80)]}=1866-324=1542
386+[48+2x(5A-80)]=1542:3=514
48+2x(5A-80)=514-386=128
2x(5A-80)=128-48=80
5A-80=80:2=40
5A=40+80=120
A=120:5=24

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