Ecuația reacției:
x 10 moli
2NaCl -------> 2Na + Cl₂
2 moli 1 mol
Rezolvare:
[tex]C=20\%\\n_{Cl_2}=10\ moli\\\\n_{NaCl}=x=20\ moli\\M_{NaCl}=A_{Na}+A_{Cl}=23+35.5=58.5\ g/mol\\\\n=\frac{m}{M}\implies m=n*M=20*58.5=1170\ g\ NaCl\ (m_d)\\\\C=\frac{m_d}{m_s}*100\implies ms=\frac{m_d*100}{C}=\frac{1170*100}{20}=5850\ g=5.85\ kg\ sol.\ NaCl[/tex]
