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Adrianalll
a fost răspuns

Rezolvati:
Prin metoda substitutiei:

x-2y=0
Acolada
4x+5y=26

Prin metoda reducerii:

4x-7y=30
Acolada
4x-5y=90

VA ROG AJUTATIMA CA AVEM INCURAND EVALUARE


Răspuns :

[tex]1)\left\{\begin{matrix}

x - 2y = 0& \\

4x + 5y = 26&

\end{matrix}\right.[/tex]

[tex]x - 2y = 0 = > x = 2y[/tex]

[tex]4x + 5y = 26[/tex]

[tex]4 \times 2y + 5y = 26[/tex]

[tex]8y + 5y = 26[/tex]

[tex]13y = 26 \: | \div 13[/tex]

[tex]y = 2[/tex]

[tex]x = 2y = > x = 2 \times 2 = 4[/tex]

[tex]2)\left\{\begin{matrix}

4x - 7y = 30& \\

4x - 5y = 90 \: | \times ( - 1) &

\end{matrix}\right.[/tex]

[tex]\left\{\begin{matrix}

4x - 7y = 30& \\

- 4x + 5y = - 90&

\end{matrix}\right.[/tex]

[tex] - 2y = - 60 \: | \div ( - 2)[/tex]

[tex]y = 30[/tex]

[tex]4x - 7y = 30[/tex]

[tex]4x - 7 \times 30 = 30[/tex]

[tex]4x - 210 = 30[/tex]

[tex]4x = 30 + 210[/tex]

[tex]4x = 240 \: | \div 4[/tex]

[tex]x = 60[/tex]