Răspuns :
[tex]\it 2x+\dfrac{1}{2}=-0,75+\dfrac{1}{3} x \Rightarrow 2x+\dfrac{1}{2}=-\dfrac{3}{4}+\dfrac{1}{3} x|_{\cdot12} \Rightarrow 24x+6=-9+4x \Rightarrow \\ \\ \\ \Rightarrow 24x-4x=-9-6 \Rightarrow 20x=-15 \Rightarrowx=-\dfrac{\ 15^{(5}}{20} \Rightarrow x = -\dfrac{3}{4}[/tex]