Răspuns:
Explicație pas cu pas:
[tex]\dfrac{2}{2+\sqrt 3}-\dfrac{2}{\sqrt 3+1}+\dfrac{2}{3\sqrt 3+5}\\\texttt{Se rationalizeaza fiecare fractie in parte.}\\\dfrac{2(2-\sqrt 3)}{4-3}-\dfrac{2(\sqrt 3-1)}{3-1}+\dfrac{2(3\sqrt 3-5)}{27-25}=\\4-2\sqrt 3-\dfrac{2(\sqrt 3-1)}{2}+\dfrac{2(3\sqrt 3-5)}{2}=\\4-2\sqrt 3-\sqrt 3+1+3\sqrt 3-5=\boxed{0}[/tex]
