Răspuns:
a1=ln(1+2/1)=ln(1+2)=ln3
a2=ln(1+2/2)=ln2
a3=ln(1+2/3)=ln5/3
a4=ln(1+2/4)=ln(1+1/2)=ln3/2
aa5=ln(1+2/5)=ln7/5
......................
an=ln(1+2/n)
bn=ln3+ln2+ln(5/3+ln3/2+ln7/5+...+ln(1+2/n)=
ln3*2*5/3*3/2*7/5*....*ln(1+2/n)=
ln6**(1+2/n)
Explicație pas cu pas:
