Răspuns
Explicație pas cu pas:
[tex]log_2\left(x+2\right)-1\:=\:log_2\left(x+1\right)\\\\\log _2\left(x+2\right)-\log _2\left(2\right)=\log _2\left(x+1\right)\\\\\log _2\left(x+2\right)=\log _2\left(x+1\right)+\log _2\left(2\right)\\\\\log _2\left(x+2\right)=\log _2\left(\left(x+1\right)\cdot \:2\right)\\\\x+2=\left(x+1\right)\cdot \:2\\\\x=0[/tex]
