Răspuns
Explicație pas cu pas:
Se aplica vesnica "metoda k" .
[tex]\dfrac{x}{3}=\dfrac{y}{4}=k\Rightarrow x=3k,y=4k\\\dfrac{2x+y}{2x-y}=\dfrac{2\cdot 3k+4k}{2\cdot 3k-4k}=\dfrac{6k+4k}{6k-4k}=\dfrac{10k}{2k}=\boxed{\bold{5}}[/tex]
