Allogucci Allogucci 28-01-2019 Matematică a fost răspuns a)2√3-4√2-(6√3-3√3+5√2)-2√2+5√3-7√2)= b)(4√11-11√11+8√11)-(7√11)+(15√11-18√11)= c)(2√7-5√7+√7)-(3√7-4√7)+(2√7-5√7)= d)(3√5-2√6+√5)-(4√5-√6)+(3√5-2√6)= e)(√2+3√3-5√2)-(4√3-√2)+(√3-2√2)= f)(3√6-√3+2√6)-(√6-4√3)+(2√6-√3)= va roooooooooooooooggggggggggg