Răspuns
[tex]\frac{2}{\sqrt{12} } - \frac{15}{5} \sqrt{3} + \frac{9}{\sqrt{27} } = \sqrt{12} - 3\sqrt{3} + \sqrt{3} = 2\sqrt{3} \\\frac{24}{\sqrt{48} } +\frac{45}{\sqrt{75} } + \frac{48}{8} \sqrt{3} = 2\sqrt{3} + 3\sqrt{3} + 6 \sqrt{3} = 11 \sqrt{3}\\ 2\sqrt{3} - 11\sqrt{3} = -9 \sqrt{3}[/tex]