1,4,5,8,9,12,13,16,17,20...
Termenii de pe pozitii impare:
T1=1; T3=5: T5=9; T7=13; T9=17
=> Tn=2n-1
Termenii de pe pozitii pare:
T2=4; T4=8: T6=12; T8=16; T10=20
=> Tn=2n
a) T11=2•11-1=21 si T12=2•12=24
b)T2015=2•2015-1=4029
c) T40=80; T39=78-1=77
=> S40=1+4+5+8+9+12+13+16+….+77+80
S40=(1+5+9+13+….+77)+(4+8+12+16+20+….80)
S40=20•(1+77)/2+20•(4+80)/2
S40=10•78+10•84
S40=1620