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Aladin aduna 4 nr. natural consecutive .Suma o imparte la 11 si obtine catul 12 si restul 6.Care sunt nr.pe care le-a adunat?

Răspuns :

Deva
a+(a+1)+(a+2)+(a+3)=S:11=12 rest 6
a+a+1+a+2+a+3=S:11=12 rest 6
4a+6=S:11=12 rest6
S=12x11+6=132+6=138
4a+6=138
4a=138-6=132
a=132:4=33
a=33
a+1=34
a+2=35
a+3=36

Vyvy0471


a=|----|

b=|----|+1

c=|-----|+2

d=|-----|+3

D:11=12 REST 6

D=11X12+6

D=138

138-6=132

132:4=33(A)

33+1=34B

34+135C

35+1=36D


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