[tex]\it\left(\dfrac{1}{7}+\dfrac{7}{11}+\dfrac{2010}{2011}\right)+\left(\dfrac{6}{7}+\dfrac{4}{11}-\dfrac{2010}{2011}\right)=\left(\dfrac{1}{7}+\dfrac{6}{7}\right) +\left(\dfrac{7}{11}+\dfrac{4}{11}\right)+\left(\dfrac{2010}{2011}-\dfrac{2010}{2011}\right)=\\ \\ \\ =1+1+0=2[/tex]
