niu,benzan= m/M= 3900g/78g/mol= 50mol
r1: C6H6+ Cl2---> C6H5Cl +HCl ORI 15a
r2: C6H6+ 2Cl2--> ortoC6H4Cl2 + 2HCl ori 2a
r3: C6H6 + 2Cl2---> para C6H4Cl2+2HCl ori 3a
r4: C6H6------------------------> C6H6 ori 5a
total 25mol
25a=50----> a=2mol
a)in r1 intra 30mol benzen si rezulta 30mol clorobenzen
=> m= niuxM=30molx112,5g/mol=..................calculeza!!!!
b) eta= niu benzen din r1x100/ niu benzen total= 30x100/50=................
c)30mol(r1)+8mol(r2)+12mol(r3)=50mol
V= niuxVm= 50x22,4 l=..........................calculeaza !!!!
