Răspuns :
(2x+1)+(x-2)=8
2x+1+x-2=8
2x+x+1-2=8
3x-1=8
(3x-1)+1=8+1
3x-1+1=9
3x=9
[tex] \frac{3x}{3} = \frac{9}{3} \\ \\ x = \frac{ {3}^{2} }{3} \\ \\ x = {3}^{2 - 1} \\ \\ x = 3 [/tex]
2x+1+x-2=8
2x+x+1-2=8
3x-1=8
(3x-1)+1=8+1
3x-1+1=9
3x=9
[tex] \frac{3x}{3} = \frac{9}{3} \\ \\ x = \frac{ {3}^{2} }{3} \\ \\ x = {3}^{2 - 1} \\ \\ x = 3 [/tex]