O rezolvare va rog!!
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x₁=A₁cos(ωt+φ₁)
x₂=A₂cos(ωt+φ₂)
x=Acos(ωt+φ)
A²=A₁²+A₂²+2A₁A₂cosΔφ=2²+6²+2*6*2*cosπ/12=4+36+26*0,96=40+25=65=>A=√65≅8 cm
tgφ=(A₁sinφ₁+A₂sinφ₂)/(A₁cosφ₁+A₂cosφ₂)=(1,73+1,55)/(1+5,79)=3,28/6,79=0,48=>φ=arctg0,48
x=Acos(ωt+φ)<=>x=8cos(πt+arctg0,48)