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Numarul de perechi de enantiomeri corespunzator monoaminelor alifatice saturate,care contin 16,09% azot este:

Răspuns :

Roberteladrianpb6zy7

CnH2n+1-NH2 = monoaminelor alifatice saturate

100% amina ................ 16,09% N

miu.amina .................... 14 g N

=> miu = 87 g/mol

=> 14n + 17 = 87

=> n = 5

=> C5H11NH2

C-C-C-C-C-NH2 = NU

C-C-C-CH(CH3)-NH2 = DA x1 pereche

C-C-C-CH(NH2)-C= DA x1 pereche

C-C(CH3)-CH(NH2)-C = DA x1 pereche

C-C-CH(NH2)-C-C = DA x1 pereche

C-C-C-C-NH-C = NU

C-C-CH(CH3)-NH-C = DA x1 pereche


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