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a fost răspuns

Va rog ma ajutati la aceasta problema ps 64 p

11 la puterea n+2 - 11 la puterea n+1+11 la puterea n
Supra
5 la puterea n+2+2•5 la puterea n+1+2•5 la puterea n

Răspuns :

[tex]\dfrac{11^{n+2}-11^{n+1}+11^n}{5^{n+2}+2\cdot5^{n+1}+2\cdot5^n}=\dfrac{11^n(11^2-11+1)}{5^n(25+10+2)}=\dfrac{111\cdot11^n}{37\cdot5^n}=\dfrac{3\cdot11^n}{5^n}[/tex]Scrie răspunsul tău aici
Veronica0
[tex] \frac{ 11^{n+2} - 11^{n+1} + 11^{n} }{ 5^{n+2}+2* 5^{n+1}+2* 5^{n} } = \frac{ 11^{n} ( 11^{2}-11+1) }{ 5^{n} ( 5^{2}+2*5+2*1) } = \frac{ 11^{n} *111}{ 5^{n} *37} [/tex]

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