Răspuns :
[tex]\it m_a=\dfrac{x+y}{2},\ m_a=16,\ y=20,\ x=?\\ \\ \\ \dfrac{x+20}{2}=16\Rightarrow x+20=2\cdot16 \Rightarrow x =32-20\Rightarrow x=12[/tex]
a+b\2 =16
a=20
20+b\2=16
20+b=16 *2
20+b=32
b=32-20
b=12
20+12\2 =32\2= 16
[tex]\it m_a=\dfrac{x+y}{2},\ m_a=16,\ y=20,\ x=?\\ \\ \\ \dfrac{x+20}{2}=16\Rightarrow x+20=2\cdot16 \Rightarrow x =32-20\Rightarrow x=12[/tex]
a+b\2 =16
a=20
20+b\2=16
20+b=16 *2
20+b=32
b=32-20
b=12
20+12\2 =32\2= 16