Răspuns :
{[4x-(32:4)]:4+38}:3=17
[(4x-8):4+38]:3=17
(x-2+38):3=17
x-2+38=51
x-2=13
x=15
verificare
{[(4*15)-(32:4)]:4+38}:3=17
[(60-8):4+38]:3=17
(52:4+38):3=17
(13+38):3=17
51:3=17
17=17
{[(a×4)-(32:4)]:4+38}:3=17
Prin metoda mersului invers :
17×3=51
51-38=13
13×4=52
32:4=8
52+8=60
4a=60
a=60:4
a=15