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a fost răspuns

(2^(n+3)×3^n+2^n×3(n+1)+6^n)÷12^n=

Răspuns :

MFM

(2^(n+3)×3^n+2^n×3(n+1)+6^n)÷12^n=

(2^n x 2³ x 3^n+2^n x 3^n x 3+6^n):12^n=

(6^n x 8+6^n x 3 +6^n):12^n=

6^nx(8+3+1):12^n=

12x6^n:12^n=(12x6^n):(2^nx6^n)=12 :2^n=3x2²:2^n=3x2^(2-n)

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