👤
a fost răspuns

a)
[tex]((\frac{18}{2 \sqrt{6} } - \frac{24}{3 \sqrt{6} } - \frac{6}{ \sqrt{6} } ) - ( \frac{8}{5 \sqrt{6} } - \frac{24}{10 \sqrt{6} } ) - ( \frac{3}{ \sqrt{6} } - \frac{12}{3 \sqrt{6} } ) [/tex]
b)
[tex]( \frac{2}{3 \sqrt{2} } + \frac{5}{ \sqrt{8} } ) - ( \frac{3 \sqrt{2} }{2} - \frac{1}{3 \sqrt{2} } )[/tex]
c)
[tex]( \frac{4}{5 \sqrt{2} } + \frac{3}{ \sqrt{8} } ) - ( \frac{5 \sqrt{2} }{4} - \frac{3}{ \sqrt{2} } )[/tex]
Multumesc!

Răspuns :

102533

Răspuns


Explicație pas cu pas:


Vezi imaginea 102533
Baiatul122001

a)

[9/(√6)-8/(√6)-6/(√6)]-[16/(10√6)-24/(10√6)]-[3/(√6)-4/(√6)]=

=(9-8-6)/√6-(16-24)/10√6-(3-4)/√6=

=(-5+1)/√6+8/10√6=

=-4/√6+8/10√6=

=(-40+8)/10√6=

=-32/10√6=

=-32√6/60=

=-8√6/15


b)

(2/3√2+5/2√2)-(3/2√2-1/3√2)=

=2/3√2+5/2√2-3/2√2+1/3√2=

=3/3√2+2/2√2=

=1/√2+1/√2=

=2/√2=

=2√2/2=

=√2


c)

(4/5√2+3/2√2)-(5/4√2-3/√2)=

=4/5√2+3/2√2-5/4√2+3/√2=

=(4+15)/5√2+(6-5)/4√2=

=19/5√2+1/4√2=

=(76+5)/20√2=

=81/20√2=

=81√2/40


Alte intrebari