Răspuns :
4x(x+1)^2 / 8(x+1) =
1/2 ·x(x+1) adica (x^2+X)/2
[tex]\it \dfrac{4x(x+1)^2}{8(x+1)} = \dfrac{\ \ 4x(x+1)(x+1)^{(4(x+1)}}{2\cdot4(x+1)}=\dfrac{x(x+1)}{2}[/tex]
4x(x+1)^2 / 8(x+1) =
1/2 ·x(x+1) adica (x^2+X)/2
[tex]\it \dfrac{4x(x+1)^2}{8(x+1)} = \dfrac{\ \ 4x(x+1)(x+1)^{(4(x+1)}}{2\cdot4(x+1)}=\dfrac{x(x+1)}{2}[/tex]