Răspuns :
Răspuns
Explicație pas cu pas:...........................................
[tex]\it E(x) =-\dfrac{7x+6}{x+2}\in \mathbb{Z} \Rightarrow \dfrac{7x+6}{x+2}\in \mathbb{Z} \\ \\ \\ \dfrac{7x+6}{x+2} = \dfrac{7x+14-8}{x+2}= \dfrac{7(x+2)}{x+2}-\dfrac{8}{x+2}= 7-\dfrac{8}{x+2}\ \in\mathbb{Z} \Rightarrow \dfrac{8}{x+2}\in\mathbb{Z} \Rightarrow\\ \\ \\ \Rightarrow x+2\in D_8\Rightarrow x+2\in \{-8,-4,-2,-1,1,2,4,8\}|_{-2}\Rightarrow x\in\{-10,-6,-4,-3,-2,0,2,6\}[/tex]