niu = nr moli si are formulele
niu = masa / M.moleculara = V / Vm (Vm = volumul molar = 22,4 in c.n.)
4.
a) 2 moli O2, V = ? L
niu = V / 22,4 => V = 22,4xniu = 22,4x2 = 44,8 L O2 (c.n.)
b) 3 moli O2, V = ? L
niu = V / 22,4 => V = 22,4xniu = 22,4x3 = 67,2 L O2 (c.n.)
5.
a) V = 44,8 L H2 , niu =? moli
niu = V / 22,4 => niu = 44,8/22,4 = 2 moli H2 (c.n.)
b) V = 22,4 L H2, niu = ? moli
niu = V / 22,4 => niu = 22,4/22,4 = 1 mol H2 (c.n.)