-Se rezolva in doua etape:
-se calculeaza nr.moli: niu=m/M
-se calculeaza nr.at: N= niuxN,A
H niu=10g/1g/mol=10mol N= 10molx6,023x10²³at= 60,23x10²³at
He = 10g/4g/mol= 2,5mol N= 2,5x6,023x10²³at=.............................
Li = 10g/7g/mol=1,43mol N= 1,43x6,023x10²³at=....................
Na = 10g/23g/mol=0,43mol.. .N= 0,43X6,023X10²³at=......................
K =10g/39g/mol=0,26mol N= 0,26X6,023X10²³at=.......................
continua !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
