niu=m/M---> niu= 175,5g/58,5g/mol= 3molNaCl
2mol........ .2mol.... ..1mol
2NaCl----> 2Na + Cl2↑ reactie ce are loc la electroliza
3mol.......x= 3mol.....y= 1,5mol
2mol......3mol.......2mol
2Fe + 3Cl2---> 2FeCl3
x.............1,5mol,,...........y
x= 1molFe pur---> m-=56g FePur-
---> p=m,px100/m,i--> m,i= 56x100/70g=80g Fe impur
y=1molFeCl3----> m= 1mol(56gFe+3x35,5gCl)/mol=.................calculeaza !!!!!