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a fost răspuns

2(x-1) +5y=3 
3x+6(y-1) =-15
Daca ati putea sa imi faceti pe pasi as aprecia.. prin metoda substitutiei

Răspuns :

Renatemambouko
2(x-1) +5y=3
3x+6(y-1) =-15

2x+5y=5
3x+6y =-9

x=(5-5y)/2
3(5-5y)/2+6y =-9
15-15y+12y =-18
3y=33
y=11

x=(5-5x11)/2=(5-55)/2=-25
Deva
2x-2+5y=3
2x+5y=5

3x+6(y-1)=-15
3x+6y-6=-15
3x+6y=-15+6=-9

x=5-5y/2
3(5-5y/2)+6y=-9
15-15Y+12y=-18
3y=33
y=11
x=5-5x11/2=5-55/2=-50/2=-25


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