[tex]\displaystyle\\(\overline{x9x} +\overline{x6})=\\=100x+90+x+10x+6=\\=100x+10x+x+90+6=\\=\boxed{111x+96}\\\\2(\overline{xx9} +\overline{8x}+7)=\\=2(110x+9+80+x+7)=\\=2(110x+80+x+9+7)=\boxed{2(111x+96)}\\\\\\111x+96~~ \text{divide} ~~2(111x+96)\\\text{Altfel spus:}\\2(111x+96)~~\text{este divizibil cu} ~~111x+96[/tex]