pana aici e bn .....
------------ aici nu e bn -----------
if l<>c then
begin
s:=0;
for l:=1 to nmax do
for c:=1 to nmax do
s:=s+m[l,c];
end;
----------------------------------------
Tr sa fie asa :
s:=0;
for l:=1 to nmax do
for c:=1 to nmax do
if l<>c then s:=s+m[l,c];
--------------------------------
dupa afisarea o faci bn