m.apa = 1,2 kg , c = 32%
stim ca c = mdx100/ms si ca ms = md + m.apa
undemd o notam cu a
=> 32 = ax100/a+1,2
=> 32(a+1,2) = 100a
=> a = 0,565 kg HCl
facem proba
=>ms = m.apa + md = 1,765 kg sol
md = 0,565 kg
=> c = mdx100/ms
= 0,565x100/1,765 = 32% deci se probeaza
