M,Na= 23g/mol
M,NaOH= 40g/mol
2Na + 2H2O----> 2NaOH + H2
22x23g....2x18g..........2x40g.........1mol
4,6g...........x.......................y.................z
x= 3,6gH2O-----> m,apa ramasa=1000-3,6=> 996,4g
y= 8gNaOH
Z=0,2molH2
c=mdx100/ms md= 8gNaOH
ms= md+m,apa= 8+996.4=. 1004,4g
c= 8x100/1004,4=.....................calculeaza !!!!!
