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Anagaina
a fost răspuns

Aratati ca: (x+2) //totul la puterea 3// - x - 2=(x+1)(x+2)(x+3) pentru orice x numar real

Răspuns :

(x+2)³-x-2=(x+1)(x+2)(x+3)
(x²+4x+4)(x+2)-x-2=(x²+3x+2)(x+3)
x³+2x²+4x²+8x+4x+8-x-2=x³+3x²+3x²+9x+2x+6
x³+6x²+11x+6=x³+6x²+11x+6
x³+6x²+11x+6-x³-6x²-11x-6=0 se reduc toti termeni
0=0

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