Răspuns
x∈{2,3}
Explicație pas cu pas:
Conditie: x ≥ -1
[tex]x\sqrt{x+1}+4=2\sqrt{x+1}+2x\\\\x\sqrt{x+1}-2x=2\sqrt{x+1} -4\\\\x(\sqrt{x+1}-2)=2(\sqrt{x+1} -2)\\\\[/tex]
[tex](x-2)(\sqrt{x+1}-2)=0[/tex]
[tex](\sqrt{x+1} -2)=0[/tex] ⇒ x=3
x-2=0 ⇒x=2
