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2moli acid acetic se obtin din alcool etilic la oxidare cu KMno4/HSO4
a) ecuatia reactiei
b) Vsolutiei kmno4/hso4, cm=2M
c)Msolutiei etanol de c=80%

Răspuns :

Roberteladrianpb6zy7

a)

CH3CH2OH + 3[O] -KMnO4/H+-> CH3COOH + H2O

b)

................................................................... 2 moli

CH3CH2OH + 3[O] -KMnO4/H+-> CH3COOH + H2O/x5

.....................................................................1x5

n moli

2KMnO4 + 3H2SO4 => K2SO4 + 2MnSO4 + 3H2O + 5[O]/x3

2x3

=> 2/5 = n/6 => n = 2,4 moli KMnO4

Cm = niu /Vs

=> Vs = niu /Cm = 2,4/2 = 1,2 L sol KMnO4

c)

md g......................................................... 2 moli

CH3CH2OH + 3[O] -KMnO4/H+-> CH3COOH + H2O

46 g/mol.......................................................1

=> md = 46x2/1 = 92 g etanol

c% = mdx100/ms

=> ms = mdx100/c% = 92x100/80

= 115 g sol etanol

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