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b=25^0+37÷[2×3^4-5×(2^7÷2^4-3^2÷3)^2]

Răspuns :

MinnieDeeya

B=25^0+37:[2x3^4-5x(2^7:2^4-3^2:3)^2]=

B= 1+37:[2x81-5x(2^3-9:3)^2]

B= 1+37:[162-5x(8-3)^2]

b=1+37:(162-5x5^2)

B= 1+37:(162-5^3)

B=1+37:(162-125)

B=1+37:37

B=1+1

B=2