[tex]\it Fie\ x,\ y,\ z \ cele\ trei\ numere.\\ \\ x+y+z=152\ \ \ (1)\\ \\ \{x, y, z\} d.\ p.\ \{3, 4, 12\} \Rightarrow \dfrac{x}{3}=\dfrac{y}{4} =\dfrac{z}{12} =\dfrac{x+y+z}{3+4+12}\ \stackrel{(1)}{=}\ \dfrac{152}{19}=8\ \ \ \ (2)[/tex]
[tex]\it (2) \Rightarrow \begin{cases}\it \dfrac{x}{3}=8 \Rightarrow x=3\cdot8=24\\ \\ \it \dfrac{y}{4}=8 \Rightarrow y=4\cdot8=32\\ \\ \it \dfrac{z}{12}=8 \Rightarrow z=12\cdot8=96\end{cases}[/tex]
