[tex]\frac{x}{y} = \frac{2}{3} => 3x=2y => x = \frac{2y}{3} \\\frac{6x+y}{9x+3y} = \frac{6 * \frac{2y}{3}+y}{9*\frac{2y}{3}+3y} = \frac{4y+y}{6y+3y} = \frac{5y}{9y} = \frac{5}{9}[/tex]
Sper ca te-am ajutat!
Daca ai intrebari da-mi mesaj.
Spor! :)
