Aici se aplica Teorema lui Thales :
AB=AE+DB=5cm+4cm=9cm
EC=>
[tex] \frac{ad}{db} [/tex]
egal cu
[tex] \frac{ae}{ec} [/tex]
=>
[tex] \frac{5}{4} [/tex]
egal cu
[tex] \frac{4}{ec} [/tex]
=> EC= 4•4:5=16:5=2,12cm
AC=AE+EC=4+2,12=6,12cm
AB=9cm
EC=2,12cm
AC=6,12cm
MULT SUCCES!!!
