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a fost răspuns

a) Stiind ca x+y+z+24=48,determinati 15+2z+2y+2x. b) Stiind ca 3x+3y+23=65,determinati 2x+2y+27. c) Stiind ca x+3y+2z+16=50,determinati 2x+6y+4z+12.

Răspuns :

Răspuns

a)   x + y + z + 24 = 48

x + y + z = 48 - 24

x + y + z = 24

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15 + 2 z + 2 y + 2 x = 63

=  15 + 2 × ( x + y + z ) =

= 15 + 2 × 24 =

= 15 + 48 =

= 63

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b)  

3 x + 3 y + 23 = 65

3 x + 3 y = 65 - 23

3 × ( x + y ) = 42

x + y = 42 : 3

x + y = 14

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2 x + 2 y + 27 = 55

= 2 × ( x + y ) + 27 =

= 2 × 14 + 27 =

= 28 + 27 =

= 55

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c)

x + 3 y + 2 z + 16 = 50

x + 3 y + 2 z = 50 - 16

x + 3 y + 2 z = 34

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2 x + 6 y + 4 z + 12 = 80

= 2 × ( x + 3 y + 2 z ) + 12 =

= 2 × 34 + 12 =

= 68 + 12 =

= 80